Why fsk is preferred over ask

Stack Overflow for Teams — Collaborate and share knowledge with a private group. Create a free Team What is Teams? Learn more. Ask Question. Asked 8 years, 7 months ago. Active 3 years, 3 months ago. Viewed 6k times. Improve this question. We observed that FSK has lesser values of signal-to-noise ratios before the probability of error reached 0. Add a comment. They are. The only difference between the coherent and non-coherent way of detection is the phase of the carrier signal.

If the carrier signal we are using at the transmitter side and receiver side are in the same phase while demodulation process i. If the carrier signals which we are using at transmitter and receiver side are not in the same phase then such modulation process known as Non-coherent detection. Another name for this detection is Asynchronous detection. In this synchronous FSK detection, the modulated wave got affected by noise while reaching the receiver. So, this noise can be eliminated from using the bandpass filter BPF.

Here at multiplier stage, the noisy FSK modulated signal is multiplied with the carrier signal from the local oscillator device.

Then the resultant signal passes from the BPF. Here this bandpass filter is assigned to cut off frequency which is equal to the binary input signal frequency. So the same frequencies can be allowed to the decision device. Here this decision device gives 0 and 1 for space and mark frequencies of the FSK modulated waveforms. The modulated FSK signal is forwarded from the bandpass filter 1 and 2 with cut off frequencies equals to space and mark frequencies.

So, the unwanted signal components can be eliminated from the BPF. Which has same probability of error? Out of the following values, which one is not possible in probability?

Explanation: In probability P x is always greater than or equal to zero. Explanation: Processing gain is given as both as the ratio of the minimum bandwidth of the data to data rate and also the by the ratio of code chip rate and data rate as minimum bandwidth is approximately equal to code chip rate.

It is usually expressed in decibels dB. Note that process gain does not reduce the effects of wideband thermal noise.

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Thread starter tabraiz Start date Mar 1, Status Not open for further replies. PaulHolland Advanced Member level 2. Yes, specially in multipath situations. Can Explain it mathematically.